In the recent years, a great effort has been made in developing a new ergodic theory for Markov processes. It concerns mainly the study on several different inequalities. Some of them are very classical but some of them are rather new. The talk introduces the inequalities and discuss their comparison. Some recent results are also reported.
| (1) |
The main inequality we are interested is the following:
| (2) |
| (3) |
Thus, we may assume in what follows that 1 < p < ¥. In view of the invariance of (2), it is natural to make the assumption that V(c f) = c2 V(f) for all constant c. However, if we take V(f) = D(f) or ||f||2, (2) is again reduced to (3).
Next, take V(f) = ||f||r2. We may also assume that r Î [1, 2) since the case that r = 2 is treated above and the case of r Î (2, ¥) can be reduced to the one of r Î [1, 2) by duality. When r = 1, it is called the Nash inequality (1958):
| (4) |
Of course, there are many other choices of V: V(f) = supx |f(x)|2, supx ¹ 0| [(f(x)-f(0))/( r(x, 0))] |2, supx ¹ y| [(f(y)-f(x))/( r(x, y))] |2, where r is a distance in E . The last one was used by Liggett (1991) and we may call the corresponding inequality the Liggett inequality.
From now on, we restrict ourselves to the case that p is a probability measure and the form (D, D (D)) satisfies D(1) = 0. Then, the right-hand side of (2) becomes zero for constant function f º 1. Thus, it is necessary to make a change of the left-hand side of (2). For this, one simply uses the variation of f: j(f) = p(f2)-p(f)2 instead of ||f||2, where p(f) = òf dp. Then we obtain the alternative form of (2) as follows.
| (5) |
Keeping the right-hand side of (3) but making a change of the left-hand side, one gets the following inequality
| (6) |
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| (7) |
There is a simple comparison between the above inequalities:
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To present some sufficient conditions for the inequalities of the form given by (1) with K(dx) = 0, we need to introduce some analogue of the isoperimetric or the Cheeger's constants. For Poincaré ineq.:
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Here only J(1/2) has not defined yet. Note that the original kernel J can be very unbounded. To avoid this, choose a symmetric founction r(x, y) so that J(1)(dx, E)/p(dx) £ 1, p-a.e., where J( a)I{r(x, y) > 0}(dx, dy) = [J(dx, dy)/( r(x, y) a )], a Î [0, 1].
Having the constants at hand, it is a simple matter to state our main result.
Theorem 1 For the form given by (1) with K(dx) = 0, if k(1/2) > 0, then the correspongding inequality in (5) or (7) holds.
We remark that even though the above condition is in general not necessary but it can be sharp qualitatively.
1 Research supported in part by NSFC (No. 19631060), Math. Tian Yuan Found., Qiu Shi Sci. & Tech. Found., RFDP and MCME.